If a polulation has dominant phenotype in 1600 individuals out of 2000 then calculate the frequency of heterozyote.. option are (1)356 (2) 256 (3)128 (4) 494 but muje solution bhi chahiye ...... ans + solution (calculation) ......
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Since we believe that the homozygous recessive for this gene (q2) represents 4% (i.e. = 0.04), the square root (q) is 0.2 (20%). The frequency of the dominant allele. Answer: Since q = 0.2, and p + q = 1, then p = 0.8 (80%). The frequency of heterozygous individuals
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