If a polygon of n sides has 1/2 n(n-3)diagonals.how many sides are there in a polygon with 65 diagonals? Is there a polygon with 50 diagonals?
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Answer:
no
Step-by-step explanation:
n(n-3)/2=65
n(n-3)=130
n^2-3n-130=0
factorize the equation
n(n-13)+10(n-13)=0
(n+10)n-13=0
n=-10or 13
the polygon with 65 diagonals have 13 sides
n(n-3)/2=50
n^2-3n-100=0
if we factorize this equation we won't get positive integers coz the sides can't be in negative nos. so we can conclude that there is no polygon with 50 diagonals
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