Question

if a polynomial 2x^3+ax^2+7x-6 is exactly divisible by 2x-1. then find the value of a.

Answer 1

Here is your answer........

Answer 2

x ^ 3 + ax ^ 2 + 7x-6 = (2x-1) (x ^ 2 + [a + 1) / 2) x + 7/2 + $\ frac {a + 1} {4}) [/ tex] + [tex] \ frac {7} {2} + \ frac {a + 1} {4} -6 [/ tex]</p><p>⇒[tex]\frac{7}{2} +\frac{a+1}{4} -6$=0

⇔a=9