if a polynomial x^4 + 5x^3 +4x^2 - 10x - 12 has two zeroes as -2 and -3 then find other zeroes
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here is your answer mate
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let the no of zeroes be X
(x+2)(x+3)
X^2+3x+2x+6
x^2+5x+6
x^2 +5x+6 is divisible by x^4+5x^3+4x^2-10x in x^2-2
splitting the middle term
(x+√2) (X-√2) is other zeroes
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