Biology, asked by nandanakk17, 5 months ago

if a population following hardy weinberg principle the frequency of dominant allele equal to 81 recessive allele equal to 19 calculate the percentage of heterozygous allele​

Answers

Answered by priyanshipareek45
2

Answer:

1. The frequency of two alleles in a gene pool is 0.19 (A) and 0.81(a). Assume that the population

is in Hardy-Weinberg equilibrium.

(a) Calculate the percentage of heterozygous individuals in the population.

According to the Hardy-Weinberg Equilibrium equation, heterozygotes are represented by the 2pq

term. Therefore, the number of heterozygous individuals (Aa) is equal to 2pq which equals

2  0.19 × 0.81 = 0.31 or 31%

(b) Calculate the percentage of homozygous recessives in the population.

The homozygous recessive individuals (aa) are represented by the q

2

term in the H-W equilibrium

equation which equals 0.81  0.81 = 0.66 or 66%

2. An allele W, for white wool, is dominant over allele w, for black wool. In a sample of 900 sheep,

891 are white and 9 are black. Calculate the allelic frequencies within this population, assuming

that the population is in H-W equilibrium.

The allelic frequency of w is represented by the q term and the allelic frequency W is represented by the

p term. To calculate the value of q, realize that qq or q

2

represents the homozygous recessive individuals

or the black sheep in this case. Since there are 9 black sheep, the frequency of black sheep

=

# individuals =

9

= 0.01 , thus ww = q

2 = 0.01

total individuals 900

 q = = = 0.1

Additionally, p + q = 1 thus p = 1 – q or p = 1 – 0.1 or 0.9  p = W = 0.9 and q = w =0.1

3. In a population that is in Hardy-Weinberg equilibrium, the frequency of the recessive

Explanation:

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