If a positive point charge 2 micro coulomb is placed at origin find the magnitude and direction of electric field at a point distant 4 m on the negative X – axis.
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Answer:
Answer
E
=
∣
r
∣
3
kq(
r
)
r
=3
i
^
+4
j
^
∣
r
∣=5
E
=
125
kq(3
i
^
+4
j
^
)
E
=
125
9×10
9
×(−2×10
−9
)(3
i
^
+4
j
^
)
E
=−0.424
i
^
−0.576
j
^
∣
E
∣=0.389
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