If a quadratic polynomial f (x) is factorizable into linear distinct factors, then what is the total number of real and distinct zeros of f(x)?
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The total number of real and distinct zeros of f(x) is two
Step-by-step explanation:
Given that a quadratic polynomial f(x) is factorizable into linear distinct factors
To find the total number of real and distinct zeros of f(x) :
- Let f(x)=ax^2+bx+c=0[/tex]
- Since the quadratic polynomial f(x) is factorizable into linear distinct factors.
- If we put the value of it must satisfy the given polynomial hence it must be a zero
- That is f(x)=0
- A quadratic equation with real coefficients can have either one or two distinct real roots. Since there are 2 distinct roots we that the discriminant is positive
- Since the given polynomial is quadratic its degree is 2
- Hence the number of zeros can be calculated with the degree of the polynomial.
- Therefore the polynomial f(x) must have two zeros
Therefore the total number of real and distinct zeros of f(x) is two
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