If a racetrack is in the form of a ring whose inner circumference is 264m and outer circumference is 30m then the width of the track is
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inner circumference (2πr) = 26.4 m
radius of outer circle = ( 26.4*7)/44
=184.8/44
=4.2 m
outer circumference (2πr)= 30
r=(30*7)/44
=210/44
=4.77 m
width of track = 4.77-4.20
= 0.57 m
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