Math, asked by himanshunimje8584, 11 months ago

Thee area of the rectangular feild is 288m square if length of a feild is twice of width what whould be parameter of feild

Answers

Answered by RANCHODE
3
answer is 12
2x(x)=288--------lxb=area of rectangle
2x^2=288
x^2=144
x=12
Answered by PriyaRathi
0

area of the rectangular field = 288m²

width = x

length = 2x

area of the rectangular field = length × width

288=2x × x

288/2=x²

144=x²

12²=x²

12m = x

Thus width = x = 12m

length = 2x = 12m×2=24m

perimeter of the rectangular field = 2(l+w)

=2(24m+12m)

=2×36m

=72m

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