if a radius of sphere reduce 20% than what will be it's valume?
Answers
Answered by
0
Answer:
Step-by-step explanation:
Let the radius be = r
The volume = 4πr³/3
When the radius is increased by 20%
The new radius is r+20*r/100 =1.2r
The new volume is = 4π(1.2r)³/3 = 1.728*(4πr³/3)
The %increase in volume = (1.728(4πr³/3)-4πr³/3)*100/(4πr³/3)=72.8%
The volume will increase by 72.8%
Answered by
0
Answer:
he/she was right__________
Similar questions