Question

If a rate of change of current of 4 ampere sec inverse induce an emf of 20 mv in a solenoid. What is the self inductance of the solenoid 2 physics

Answer 1

Dear Student,

◆ Answer -

L = 5 mH

● Explaination -

# Given -

di/dt = 4 A/s

e = 20 mv = 20×10^-3 V

# Solution -

Value of self-inductance is calculated by -

L = e / (di/dt)

L = 20×10^-3 / 4

L = 5×10^-3 H

L = 5 mH

Therefore, self inductance of the solenoid must be 5 mH.

Thanks dear...

Answer 2

Answer:

5mH

Explanation:

The correct answer is 5mH

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