If a regular polygon has 54 diagonals, what is the measure of each interior angle of the polygon
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The number of diagonals for a polygon having n sides is given by n∗(n−3)/2
You can easily derive it.
Diagonal is a line segment joining two edges of the polygon which are already not a polygon edge.
The number of edges from n sides will be nC2 .
The number of edges will be n .
Therefore, total number of diagonals = nC2−n
= n∗(n−3)/2
Now,
n∗(n−3)/2=54
=>n2−3n=108
=>(n−12)(n+9)=0
Solving this, you get
n=12
Interior angle sum = (n - 2 ) * 180
= ( 12 - 2 ) * 180
= 1800
each angle = = 150
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