Question

The rth term of an AP is (3r-1)/6.The sum of the first P terms of series is​

Answer 1

Answer:

nsnsnsmmsnsnssnnsnsnsnnsnsnsnsnssnnsnsnsn

n(n+1) /2

Answer 2

Answer:

The first term is (3*1-1)/6 = 2/6 

The rth term is (3r-1)/6 

The average of the first term and the last term is

1/2*( 2/6 + (3r-1)/6 ) 

=(2+3r-1)/12 

= (3r+1)/12 

So the sum of the first p terms is p * (3r+1)/12 = (p/12)(3r+1). 

Step-by-step explanation:

We found : a = 2/6

Given : last term = (3r-1)/6

Sum of first p terms = p/2 * [ 2/6 + (3r-1)/6]

Solving we would get = (p/12) (3r + 1)