if a right circular cylinder just encloses a sphere of radius R find curved surface area of the cylinder
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here, radius of sphere is also R (cyclinder is closed)
so, surface area = 4 pi R*R
Patilpranavkumar:
hey hai
??
Yes
Answered by
10
Given,
The cylinder just encloses a sphere of radius 'R'.
So the radius of cylinder is also 'R' units.
Now.By formulae for CSA of a cylinder.→2πrh
The CSA of the given cylinder would be
→2πR(h) →(1)
Now,Since the Cylinder encloses the sphere of Radius 'R'. The height of the cylinder would be the diameter of the sphere ,ie =2R.
So (1) becomes...
2πR(2R)
=4πR² unit²
So, 4πR² sq.units is your required CSA for the given Cylinder.(Provided it just encloses a sphere of radius 'R'.)
Hope it Helps...
Regards,
Leukonov.
The cylinder just encloses a sphere of radius 'R'.
So the radius of cylinder is also 'R' units.
Now.By formulae for CSA of a cylinder.→2πrh
The CSA of the given cylinder would be
→2πR(h) →(1)
Now,Since the Cylinder encloses the sphere of Radius 'R'. The height of the cylinder would be the diameter of the sphere ,ie =2R.
So (1) becomes...
2πR(2R)
=4πR² unit²
So, 4πR² sq.units is your required CSA for the given Cylinder.(Provided it just encloses a sphere of radius 'R'.)
Hope it Helps...
Regards,
Leukonov.
ok , i'm going
In normal case... that is true... Here... given the Cylinder just encloses the sphere. So height =2R.
Then Tell me How you got "4πR*R".???
ok, but it doen't matter
Hmmm....
let's just leave at that then... For the better.
because area of sphere is only depends on R of sphere , here R = radius of cyclinder,
it is independent of Hight
it is independent of Hight
but surface are of cylinder is asked.
ok sorry, its my mistake
Well... Whatever... Though our methods may be different, We got the same answer... All the same.
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