if a = root 5 + 3 / root 5 -3 and b = root 5 - 3 / root 5 + 3 , find the value of a ^2 + b^2 + ab
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Answer:
a=(√5+3)/(√5-3)
b=(√5-3)/(√5+3)
ab=(√5+3)/(√5-3)×(√5-3)/(√5+3)=1
a+b=(√5+3)/(√5-3)+(√5-3)/(√5+3)
=(√5+3)^2+(√5-3)^2/(√5+3)((√5-3)
=(5+9+6√5+5+9-6√5)/(√5^2-3^2)
=28/(5-9)
=28/-4
= -7
a^2+b^2+ab
=(a+b)^2-2ab+ab
=(-7)^2-ab
= 49-1
= 48
Hope it helps!!
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