if a=root10+ root 5 by root 10- root 5 and b =root10 - root 5by root10 + root 5 then prove that roota + root b- 2rootab =0
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√10+√5/√10–√5=b
√10–√5/√10+√5=a
√a+√b–2√ab=0
by adding equation a by b
gives 10=ab
2√ab = 2√10
=2(100)/200
=200/200
=0
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