If a=root3 +root2/root3-root2 and b=root3-root2/root3+root2, Find the value of 3(a²-b²)
Answers
Answered by
1
Answer:
50
Step-by-step explanation:
a = (root 3+root 2/root 3- root 2)(root 3+root 2/root 3+root 2)
a=3+2+2(root 3)(root 2)
a=5+2root 6
b=(root 3-root 2/root 3+ root 2) (root 3- root 2)
b-5- 2root 6
a square+ b square=(5+ 2 root 6) square + (5-2 root 6)square
a square + b square=25+(4)(6)+25-(4)(6)
a square + b square=25+24+(25-24)
a square + b square=49+1
a square + b square=50
Answered by
2
Answer attached pls mark as brainliest.
hope it helps u
Attachments:
Similar questions