If a=root3-root2 upon root3+root2 and b=root3+root2 upon root3-root2 then find the value of a^2+b^2-5ab...
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A=√3-√2/√3+√2
B=√3+√2/√3-√2
RATIONALISING THE DENOMINATOR FOR THE BOTH A AND B
A=(√3-√2)X(√3-√2)/(√3+√2)(√3-√2)
=(√3-√2)²/(√3)²-(√2)²
=3 -2√6 +2/3-2=5-2√6
B=(√3+√2)X(√3+√2)/(√3-√2)X(√3+√2)
=5+2√6 .....................FROM ABOVE
A² +B² - 5AB=(A+B)² -2AB -5AB=(A+B)² - 7AB ........(A+B)=A²+B² 2AB
=(5-2√6+ 5+2√6)²-7(5-2√6)(5+2√6)
=(5)² -7((5)² - (2√6)²)
=25 - 7(25 -24)
=25 - 7(1)
=25 -7=18
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