Question

if A's income is 10% less than that of B by what percent is income more than A's

Answer 1

Let the income of A be ₹100.

Then income of B =90%of100=₹90.

Rate by which income of B mire than the income of A =₹100-₹90=₹10.
Therefore %=₹10/₹90×10=11.11%(approx.)

Answer 2

If A's income is less than B's income then the A's income will be=
less 10% = 100-10=90%
therefore, 90+10= 100%

percentage of B's income more than A is=

$\frac{90}{100} \times 100 = 90\%$
Hence,percentage of B's is income more than A's income is 90%

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