if a's income is less than b's income by 20% , then by what % is b's income more than a's?
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b's income is more than a's by 80%
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Let the income of 'a' be Rs. A and of 'b' be Rs.B ;
If A is 20% less than that of B then 100%-20% of B = A
⇒ 80% B = A
⇒ B = (100/80) of A = 10 / 8 % of A = 1.25 % of A
Hence, the income of b is 1.25 % more than that of a.
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If A is 20% less than that of B then 100%-20% of B = A
⇒ 80% B = A
⇒ B = (100/80) of A = 10 / 8 % of A = 1.25 % of A
Hence, the income of b is 1.25 % more than that of a.
i hope the answer is correct !
Please mark the answer as the brainliest if u r satisfied !
Thank you !
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