Question

If a sample of ferric sulphate contains 7.2 moles of oxygen atom the number of atoms in the given sample are

Answer 1

Explanation:

molar mass=399.88g/mol

Fe2(SO4)3

total number of oxygen atoms is 4×3=12 o atoms

molar mass ofO12=12×16=192g/mol

no of moles of oxygen atoms is 7.2mol

n=m/molar mass

m=n×mm

7.2×192 =1382.4g

7.2mol=7.2×6.02×10^23=43.344oxygen atoms

Fe2(SO4)3

3 s atoms

no of moles = no of atoms/avg numbr

=3/6.02×10^23moles=3/6.02×10^23×6.02×10^23=

3 s atoms

and 2 fe atoms