Question

If a saturated solution prepared by dissolving Ag2CO3 in water has [Ag+]=2.5×10^-4. What is the value of Ksp for Ag2CO3?

Answer 1

Ag2co3 would be dissociated as 2Ag+ and CO3^2-, so

      Ag2co3 = 2Ag^+ + CO3^2-

If dissociation is x than

         Ksp = (2x)^2 * x

                 = 4x^3

Here x= 2.5*10^-4

     Therefore

       Ksp= 4*(2.5*10^-4)^3

              = 6.25*10^-11

             

Answer 2

The value of $K_{sp}$ for $Ag_{2}CO_{3}$ is $7.81 \times 10^{-12}$.

Explanation:

The reaction equation will be as follows.

          $Ag_{2}CO_{3} \rightarrow 2Ag^{+} + CO^{2-}_{3}$

As it is given that the $[Ag^{+}]$ is $2.5 \times 10^{-4}$. So, the value of $CO^{2-}_{3}$ is as follows.

                $[CO^{2-}_{3}] = \frac{2.5 \times 10^{-4}}{2}$

                             = $1.25 \times 10^{-4}$

Therefore, expression for $K_{sp}$ is as follows.

               $K_{sp} = [2s]^{2}[s]$

                          = $(2 \times 1.25 \times 10^{-4})^{2} \times (1.25 \times 10^{-4})$

                          = $7.81 \times 10^{-12}$

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