Question

if a scooter acquires a velocity of 36km/h in 10s just after its start then the application of scooter is

Answer 1

36 km/h=36×1000/3600 m/s
=10 m/s
u=0
v=10m/s
t=10 s
a=10_0/10m/s^2
=1 m/s^2
so,acceleration=1 m/s^2
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Answer 2

GIVEN , INITIAL VELOCITY , u = 0m/s
FINAL VELOCITY, v = 36km/hr
= 10m/s
TIME = 10secs .

THEREFORE, ACCORDING TO THE 1ST EQUATION OF MOTION,

v = u + at ,
we get .....

10 = 0 + a × 10
=> 10 = 10a
=> 1 = a

THEREFORE, THE ACCELERATION = 1m/s^2