If a semiconductor has an intrinsic carrier concentration of 1.41 × 1016/m3, when doped with 1021/m3 phosphorous atoms, then the concentration of holes/m3 at room temperature will be (a) 2 × 1021 (b) 2 × 1011 (c) 1.41 × 1010 (d) 1.41 × 1016
Answers
Answered by
0
Answer:
option c
d
Explanation:
Droping wil increasse the number of electrons only nad not the holes. So, number of holes will be equal to number of intrinsic carrier concentration.
=1.41×1016/m3
Answered by
4
Answer:
Concentration = 1.41 × 10¹⁶/m³
Explanation:
We know that,
Doping will increase the number of electrons only and not the holes.
So,
Number of holes will be equal to number of intrinsic carrier concentration
i.e.,
Concentration = 1.41 × 10¹⁶/m³
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