if a sin theta + b cos theta equal to C then prove that A cos theta minus B sin theta is equal to plus minus root a square + b square minus C square
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in a triangle angle a + angle b + angle c is equal to 180 degree therefore angle a is equal to b + c by 180
devchugh84:
le bhai
a sin theta + b cos theta whole square +a cos theta minus b sin theta whole square
a sin square theta + b cos square theta
+ 2 AV sin cos + a square cos square theta + b sin square minus 2 a b sin cos theta
a a square sin square theta + cos square theta whole square + b sin square theta + cos square theta
is equal to a square + b square as sin square theta + cos square theta
c square (
a cos theta minus b sin theta whole square is equal to a square + b square
a bracket cos theta minus b sin theta is equal to a square + b square minus
hence proved
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Step-by-step explanation:
Given
Afterwards add both the equation
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