Math, asked by harshit182565, 1 year ago

if a sin theta + b cos theta equal to C then prove that A cos theta minus B sin theta is equal to plus minus root a square + b square minus C square

Answers

Answered by devchugh84

in a triangle angle a + angle b + angle c is equal to 180 degree therefore angle a is equal to b + c by 180

devchugh84: le bhai

devchugh84: a sin theta + b cos theta whole square +a cos theta minus b sin theta whole square

devchugh84: a sin square theta + b cos square theta

devchugh84: + 2 AV sin cos + a square cos square theta + b sin square minus 2 a b sin cos theta

devchugh84: a a square sin square theta + cos square theta whole square + b sin square theta + cos square theta

devchugh84: is equal to a square + b square as sin square theta + cos square theta

devchugh84: c square (

devchugh84: a cos theta minus b sin theta whole square is equal to a square + b square

devchugh84: a bracket cos theta minus b sin theta is equal to a square + b square minus

devchugh84: hence proved

Answered by kundan23123

Answer:

Step-by-step explanation:

Given

Afterwards add both the equation

Attachments:

Previous Question

Next Question