Question

If a solid metallic sphere of radius 16 cm is melted

and recast into m-spherical solid balls of radius

2 cm, then the value of m is equal to​

Answer 1

Answer:

m = 512

Step-by-step explanation:

radius of sphere = 16 cm

radius of balls formed = 2cm

volume of bigger sphere = m × volume of balls

$\frac{4}{3} \pi {r1}^{3} = m \times \frac{4}{3} \pi {r2}^{3} \\ {r1}^{3} = m \times {r2}^{3} \\ {(16)}^{3} = m \times {2}^{3} \\ m = \frac{ {16}^{3} }{ {2}^{3} } \\ m = {( \frac{16}{2}) }^{3} \\ m = {8}^{3} \\ m = 512$

hope you get your answer