if a solid right circular cylinder made of iron is heated to increase its radius and height by 1% each, then by how much per cent does the volume of the solid increase?
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The volume of the cylinder gets changed by 2 whole of 1/100%.
Step-by-step explanation:
Let, the radius of the cylinder be, 'r'
The height of the cylinder be, 'h'
∴ Volume of the cylinder = πr²h
After heating, the radius of the cylinder becomes,
r+ (r*1/100)
= r+r/100
=(100r+r)/100 [∵ The L.C.M. of the denominators is 100.]
= 101r/100
∴ New volume of the cylinder
= π(101r/100)²h
= 10201πr²h/10000
∴ The change in volume_
(10201πr²h/10000) - πr²h
=(10201πr²h - 10000πr²h)/10000 [∵ The L.C.M. of the dinominators is 10000]
= 201πr²h/10000
∴ The changed % in volume_
{(201πr²h/10000)/πr²h}*100
= (201πr²h*100)/ (10000*πr²h)
= 201/100
= 2 whole of 1/100 %.
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