Question

if a solid shell loses half of its weight in water and the relative density of shell is5 .then what fraction of the body is hollow

Answer 1

The volume of water displaced is the force experienced on the shell, which is the weight lost by the shell. Let the volume of the entire shell be "V", and the volume of the hollow part be "v". Now, weight of the shell is 5*(V-v)*g. Weight of the water displaced is V*g.

5*(V-v)*g = V*g

From the above equation, we get v/V = 4/5.

Therefore, the fraction of body which is hollow is 4/5