Question

if a solution is formed by mixing 0.1M H2SO4 (100ml) and 0.1M HCl (200ml), then molarity of [H+] in the resulting solution is

Answer 1

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Answer 2

Answer: The concentration of $H^+$ ions in the resulting solution is 0.133 M.

Explanation:

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

$M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of the $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of the HCl

We are given:

$n_1=2\\M_1=0.1M\\V_1=100mL\\n_2=1\\M_2=0.1\\V_2=200mL$  

Putting all the values in above equation, we get:

$M=\frac{(2\times 0.1\times 100)+(1\times 0.1\times 200)}{100+200}\\\\M=0.133M$

The concentration of $H^+$ ions in the resulting solution will be same as the molarity of solution which is 0.133 M.

Hence, the concentration of $H^+$ ions in the resulting solution is 0.133 M.