If a solution of 10^-6 m hcl is diluted 100 times the ph of solution is
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A solution with pH 6 has concentration 10-6 M
If it is diluted 1000 times, it becomes 10-6/1000 = 10-9 M
Water has a pH = 7. Thus, [H3O+] in water = 10-7 M
Now, the [H3O+] in dilute acidic solution will approach 10-7 M. The concentration can not become less than 10-7 M due to dissociation of water to H3O+.
So, pH of resulting solution will be approx. 6.96.
If it is diluted 1000 times, it becomes 10-6/1000 = 10-9 M
Water has a pH = 7. Thus, [H3O+] in water = 10-7 M
Now, the [H3O+] in dilute acidic solution will approach 10-7 M. The concentration can not become less than 10-7 M due to dissociation of water to H3O+.
So, pH of resulting solution will be approx. 6.96.
Answered by
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Answer:Answer:10^-6 m hcl has pH=6
Now,after diluting [H^+] =10^-6÷100=10^-8
So,10^-8 [H^+] will come from Acid and 10^-7 [H^+] will come from water (it is pre assumed at 25℃ )
Now, total [H^+] = 10^-7 + 10^-8 =11 × 10^-8
Therefore , the new pH will be=
-log[H^+]=-log[11×10^-8]
=-log11 -log10^-8
=8 -log11
=8 - 1.0413=6.958(Answer)
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