if a splash is heard 4.23seconds after a stone is dropped into a well 78.4 m deep. find the speed of sound in air
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Now to find the velocity, we are now to go use the formula
T=2d/v
T=time
D=distance
V=velocity
V=2×78.4/4.23
=156.8/4.23
=37.06 m/s
Assuming no air (or air drag) on stone, the time it takes the stone to reach water is:
t = √2h/g
= √2(78.4)/9.81
= √15.98369
= 3.998 s
time for sound to travel 78.4 m = 4.23 - 3.998
= 0.232 s
speed of sound in well = 78.4/0.232
= 338 m/s
T=2d/v
T=time
D=distance
V=velocity
V=2×78.4/4.23
=156.8/4.23
=37.06 m/s
Assuming no air (or air drag) on stone, the time it takes the stone to reach water is:
t = √2h/g
= √2(78.4)/9.81
= √15.98369
= 3.998 s
time for sound to travel 78.4 m = 4.23 - 3.998
= 0.232 s
speed of sound in well = 78.4/0.232
= 338 m/s
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