Question

if a square + 1 by a square is equal to 47 and is not is equal to zero find a + 1 by a​

Answer 1

Answer:let a=x

Step-by-step explanation:

Answer 2

$\frac{ {a }^{2} + 1}{ {a}^{2} } = 47 \\ {a}^{2} + 1 = 47 {a}^{2} \\ 46 {a }^{2} = 1 \\a = \sqrt{ \frac{1}{46} } \\ a = \sqrt{ \frac{1}{2 \times 23} }$

HOPE help you

After putting the value of a

Answer is 1+underroot 46