If a square +b square =45&ab=18,then 1/a+1/b is
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Hola there,
According to the question,
=> a² + b² = 45. and ab = 18
Now, as we know,
=> (a + b)² = a² + b² + 2ab
Putting values we get
=> (a + b)² = 45 + 36
=> (a + b)² = 81
=> a + b = 9. ... equation 1
From given, ab = 18
We can write b = 18/a
Put the value in equation 1, we get..
=> a + 18/a = 9
=> a² + 18 = 9a
=> a² - 9a + 18 = 0
=> a² - 3a - 6a + 18 = 0
=> a(a - 3) -6(a - 3) = 0
=> (a - 3)(a - 6) = 0
=> a = 3 or 6
Now b = 18/3 or 18/6
= 6 or 3
So, 1/a + 1/b when a = 3 and b = 3
= 2/3
1/a + 1/b when a = 6 and b = 6
= 2/6 = 1/3
1/a + 1/b when a = 6 and b = 3
= 3/6 = 1/2
1/a + 1/b when a = 3 and b = 6
= 3/6 = 1/2
Hope this helps....:)
According to the question,
=> a² + b² = 45. and ab = 18
Now, as we know,
=> (a + b)² = a² + b² + 2ab
Putting values we get
=> (a + b)² = 45 + 36
=> (a + b)² = 81
=> a + b = 9. ... equation 1
From given, ab = 18
We can write b = 18/a
Put the value in equation 1, we get..
=> a + 18/a = 9
=> a² + 18 = 9a
=> a² - 9a + 18 = 0
=> a² - 3a - 6a + 18 = 0
=> a(a - 3) -6(a - 3) = 0
=> (a - 3)(a - 6) = 0
=> a = 3 or 6
Now b = 18/3 or 18/6
= 6 or 3
So, 1/a + 1/b when a = 3 and b = 3
= 2/3
1/a + 1/b when a = 6 and b = 6
= 2/6 = 1/3
1/a + 1/b when a = 6 and b = 3
= 3/6 = 1/2
1/a + 1/b when a = 3 and b = 6
= 3/6 = 1/2
Hope this helps....:)
SsSapnapilania:
Correct thanks
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