Question

if a square + b square +c square is equal to 200 and ab +bc +ca is equal to 28 then find the value of a+ b +c​

Answer 1

Hope it helps you out

Mark it brainliest.....

Answer 2

Answer :- + - 16

Given :-

${a}^{2} + {b}^{2} + {c}^{2} = 200 \\ ab + bc + ca = 28 \\ a + b + c =$

$(a + b + c) ^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca)$

$(a + b + c) ^{2} = 200 + 2 \times 28$

$(a + b + c) ^{2} = 200 + 56$

$(a + b + c) ^{2} = 256$

$(a + b + c) ^{2} = ( + - 16) ^{2} \\ a + b + c = + - 16$

[ Taking square root of both sides ]