Question

if a square + b square is equal to 79b then prove that 2 log of a + b is equal to 4 log 3 + log a + log b​

Answer 1

Answer:

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Answer 2

given that= a²+b²=79ab

prove that =2log(a+b)=4log3+loga+logb

adding 2ab on both sides

a²+b²+2ab=79ab+2xy

(a+b)²=81ab

Adding log on both sides

log(a²+b²)=log81ab

2log(a²+b)=log81+loga+logb

2log(a+b)=log3⁴+loga+logb

2log(a+b)=4log3+loga+logb

therefore hence proved