if a square is inscribed in a circle, what is the ratio of the areas of the circle and the square? pls give full answer with steps
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Diagonal of the square. = Diameter of the circle
diagonal of a sq = √2 a
Radius of the circle = √2 a / 2
= a/√2
area of the circle = π r sq
= π × a / √2 × a/√2
= π a sq / 2
area of sq = a sq
ratio = π a sq / 2× a sq
= π : 2
diagonal of a sq = √2 a
Radius of the circle = √2 a / 2
= a/√2
area of the circle = π r sq
= π × a / √2 × a/√2
= π a sq / 2
area of sq = a sq
ratio = π a sq / 2× a sq
= π : 2
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parmarfreya12:
thnx
Answered by
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Answer:
Diagonal of the square. = Diameter of the circle
diagonal of a sq = √2 a
Radius of the circle = √2 a / 2
= a/√2
area of the circle = π r sq
= π × a / √2 × a/√2
= π a sq / 2
area of sq = a sq
ratio = π a sq / 2× a sq
= π : 2
Attachments:
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