If a square is inscribed in a circle, what is the ratio of the area of the circle and the square?
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FIGURE IS IN THE ATTACHMENT.
Let ABCD be a square inscribed in a circle of radius ‘r’. OA =OB= OC = OD = r
Diagonal AC = OA + OC = r + r = 2r
Let ‘a’ be the length of a side of the square.
Diagonal of Square (AC) = √2 × side = √2a
√2a = 2r
a = 2r/√2 =( 2r × √2) / (√2×√2) = 2√2r/2= √2r
[Rationalising the denominator]
a = √2r
Area of a square = side² = a² = (√2r)²= 2r²
Area of circle = πr²
Area of circle : Area of a square
πr² : 2r²
π : 2
Hence, the ratio of the area of the circle and the square is π : 2.
HOPE THIS WILL HELP YOU...
FIGURE IS IN THE ATTACHMENT.
Let ABCD be a square inscribed in a circle of radius ‘r’. OA =OB= OC = OD = r
Diagonal AC = OA + OC = r + r = 2r
Let ‘a’ be the length of a side of the square.
Diagonal of Square (AC) = √2 × side = √2a
√2a = 2r
a = 2r/√2 =( 2r × √2) / (√2×√2) = 2√2r/2= √2r
[Rationalising the denominator]
a = √2r
Area of a square = side² = a² = (√2r)²= 2r²
Area of circle = πr²
Area of circle : Area of a square
πr² : 2r²
π : 2
Hence, the ratio of the area of the circle and the square is π : 2.
HOPE THIS WILL HELP YOU...
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