Question

If a standard barometer reading 760mm of mecury correspond to a pressure of 10^5 pa acting on the free surface of mercury in the reservior, what is the atmoshperic pressure when the barometer reads 570mm of mercury

Answer 1

Answer:

Explanation:

(Ans. 7.5 x 10 Pa) hill station on a particular day, the barometer reads 700 mm of ... Pa) If the standard barometer reading of 760 mm of mercury corresponds to a pressure of 105 Pa acting on the free surface of mercury in the reservoir, what is the atmospheric pressure (in Pa) when the barometer reads 570 mm of mercury ?

Answer 2

Answer:

Answer :

0.75 × 10⁵ Pa

Explanation:

$here \\ \: 760mm \: of \: hg \: = {10}^{5} pa \\ when \: barometer \: reads \: 570mm \: the \: pressure \: is \\ ( \frac{570}{760} \times {10}^{5} )pa \\ = \frac{3}{4} \times {10}^{5} pa \\ = 0.75 \times {10}^{5} pa$