if a stone is dropped in a well and the sound of splash us heard after 2.056 second.if the the value of g=9.8m/s^2.find the depth of well.take speed of sound=350m/s
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Answer:
6250 m
Explanation:
u = 0 m/s
v = 350 m/s
a = g = 9.8 m/s^2
s(dis.) = ?
So, we apply the equation v^2 - u^2 = 2as
=》(350)^2 - (0)^2 = 2(9.8)s
=》122500 - 0 = 19.6s
=》122500 = 19.6s
=》122500/19.6 = s
=》6250 = s
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