Question

If a stone is thrown up ward with a velocity of 20 m/sec what is the maximum height to reach​

Answer 1

$\huge\fcolorbox{red}{cyan}{20\:m}$

Explanation:

• Final Velocity(v) = 0 m/s

• Initial Velocity(u) = 20 m/s

• Accleration(a) => -10 m/s²

• Distance(s) = ?

Third Equation of Motion :-

$\large\fbox\color{purple}{v²=u²+2as}$

Lets Put The Values :-

$0²=20²+(2 \times -10 \times s) \\ =>0=400 - 20s \\ =>-400 = -20 s \\ => s = \frac{-400}{-20} \\ =>\boxed{s=20}$

Hope it helped