If a stone is thrown vertically upwards to a height of 9.8m, calculate (i) the velocity with which it was thrown and (ii) time taken by it to reach the highest point. Take g 10m/s2
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Answered by
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Hi friend
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Your answer
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Height to which a stone was thrown = 9.8 m
To calculate : -
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(i) Velocity (Initial)
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v = 0 m/s , s = 9.8 m , a = g = - 10 m/s² [stone us thrown upwards, so against gravity, acceleration will be negative]
v² - u² = 2 × g × s
=> (0)² - u² = 2 × 10 × ( -9.8 )
=> - u² = - 196
=> u² = 196
=> u = √196
=> u = 14 m/s
(ii) Time taken to reach the highest point
--------------------------------------------------------------
v = u + at
=> 14 = 0 + 10 × t
=> 14 = 10t
=> t = 14/10
=> t = 1.4 seconds
HOPE IT HELPS
#ARCHITECTSETHROLLINS
✯ BRAINLY STAR ✯
----------------
Your answer
----------------------
Height to which a stone was thrown = 9.8 m
To calculate : -
------------------------
(i) Velocity (Initial)
----------------------------
v = 0 m/s , s = 9.8 m , a = g = - 10 m/s² [stone us thrown upwards, so against gravity, acceleration will be negative]
v² - u² = 2 × g × s
=> (0)² - u² = 2 × 10 × ( -9.8 )
=> - u² = - 196
=> u² = 196
=> u = √196
=> u = 14 m/s
(ii) Time taken to reach the highest point
--------------------------------------------------------------
v = u + at
=> 14 = 0 + 10 × t
=> 14 = 10t
=> t = 14/10
=> t = 1.4 seconds
HOPE IT HELPS
#ARCHITECTSETHROLLINS
✯ BRAINLY STAR ✯
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