Question

solution of
$6 {x}^{2} - bx + 2 \: is \: 1$

Answer 1

Heya,

Given:

Equation : 6x² - bx + 2

Solution of equation is 1, so;

=> 6(1)² - b(1) + 2 = 0

=> 6 - b + 2 = 0

=> 8 - b = 0

=> b = 8

Hope this helps....:)

Answer 2

Solution of equation is 1 so put 1 in place of x
6x^2 -bx +2 =0
6 (1)^2 -b (1) +2 =0
6-b+2 = 0
8-b =0
b =8