if a student scores 35% in a test and he is failed by 42 marks but when he scores 48% marks in the same test he is passed by 62 marks . find yhe passing percentage for the test
Answers
Answer:
he boy scored 35% of the maximum marks.
This means,
(35/100) * m = Marks obtained.
But he falls short by 10 marks to pass the exam.
Therefore marks required for passing
= Marks obtained + 10
Passing marks = (35/100) * m + 10.
Now if he had scored 46% of the maximum marks i.e. (46/100) * m
He would have cleared his passing marks by 12.
This means that the 46% is more than passing marks by 12.
Passing marks = (46 /100) * m - 12.
Equating both the values of passing marks
(35/100) * m + 10 = (46/100) * m - 12.
Taking like terms on the same sides.
10 + 12 = ( 46/100) * m - (35/100) * m
22 = (11/100) * m
(22/11) * 100 = m
m = 200 = Maximum Marks.
Now putting this value of 'm' in any of the 2 passing marks equations formed earlier.
Passing marks = (35/100) * m + 10.
= (35/100) * 200 + 10.
= 80.
Step-by-step explanation:
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