If a successive telephone post are 20m apart along a straight road and and a car pass to the first to the thirteen in 16 seconds,how fast the car is travelling in km/hr?
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d=13×20=260m
t=16 sec
speed=dis/time
so,
speed=260/16
=16.25mps
now,
16.25×18/5
ans=58.5kmph
t=16 sec
speed=dis/time
so,
speed=260/16
=16.25mps
now,
16.25×18/5
ans=58.5kmph
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