If a sum of rs.3540 is divided in three parts in a ratio of 2:6:7 , then the largest part will be:
Answers
Answered by
9
The answer is given below :
The ratio of the numbers is 2 : 6 : 7
Let, the common multiple be x
Then the numebers are 2x, 6x and 7x
Given,
sum of the numbers = 3540
=> 2x + 6x + 7x = 3540
=> 15x = 3540
=> x = 236
So, the required numbers are
2×236, 6×236 and 7×236
i.e., 472, 1416 and 1652
So, the largest part is 1652.
Thank you for your question.
The ratio of the numbers is 2 : 6 : 7
Let, the common multiple be x
Then the numebers are 2x, 6x and 7x
Given,
sum of the numbers = 3540
=> 2x + 6x + 7x = 3540
=> 15x = 3540
=> x = 236
So, the required numbers are
2×236, 6×236 and 7×236
i.e., 472, 1416 and 1652
So, the largest part is 1652.
Thank you for your question.
Answered by
1
Hii friend,
Let the ratio be 2X , 6X, and 7X.
Sum of the ratio = 3540
Therefore,
2X+6X+7X = 3540
15X = 3540
X = 3540/15
X = 236
Therefore,
2X= 2 × 236 = 472
6X = 6×236 = 1416
7X = 7 × 236 = 1652
Therefore,
The largest part = 1652
HOPE IT WILL HELP YOU..... :-)
Let the ratio be 2X , 6X, and 7X.
Sum of the ratio = 3540
Therefore,
2X+6X+7X = 3540
15X = 3540
X = 3540/15
X = 236
Therefore,
2X= 2 × 236 = 472
6X = 6×236 = 1416
7X = 7 × 236 = 1652
Therefore,
The largest part = 1652
HOPE IT WILL HELP YOU..... :-)
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