Question

If a sum on compound interest becomes three times in 4 years

Answer 1

complete the question pls

Answer 2

Let the sum be P

The sum P becomes 3P in 4 years of compound interest

3P=P(1+R/100)^4⇒3=(1+R100)4

Let the sum P becomes 81P in n years

81P=P(1+R100)n⇒81=(1+R/100)^n ⇒ (3)^4 = (1+R/100)^n ⇒ ((1+R/100)4)^4=(1+R/100)^n⇒(1+R/100)^16=(1+R/100)^nn=16

i.e, the sum will become 81 times in 16 years