if a tower 30m high,casts a shadow 10under root 3 m long on the ground then what is the angle of elevation of the sun?
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Answer:
60°
Step-by-step explanation:
Let AB be the tower and BC be the shadow.
AB = 30 cm and BC = 10√3.
∴ Tan θ = AB/BC
= 30/10√3
= (10 * 3)/10√3
= √3
⇒ Tan θ = (√3)
⇒ Tan θ = Tan 60
⇒ θ = 60.
Therefore, Angle of elevation of the sun = 60°.
Hope it helps you.
#Bebrainly
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