Question

If a tower is 30m high,casts a shadow 10√3long the ground,then what is the angle of elevation of the sun

Answer 1

Let theta be the angle of elevation of sun.
tan theta = height of tower ÷ length of shadow
in this case tan theta
= 30/10√3
= √3
since tan theta is √3 the theta is 60 degrees
therefore the angle of elevation is 60 degrees.
hope this will help u

Answer 2

Draw a rightΔABC in which AB=30 m,BC=10√3 m
In ΔABC,
AB/BC=tan∠ACB
30/10√3=tan∠ACB
√3=tan∠ACB⇒tan 60°=tan∠ACB [√3=tan 60°]
⇒∠ACB=60°
∴Hence,the angle of elevation of the sun is 60°.