If a train accerlating uniformly at 5m / s square attains a velocity of 90km / h. after the start find it's displacement and time for which if accerlates
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simran331:
Oh sorry, I haven't seen the picture
But thanx for give me the answer
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Given data
a= 5m/s^2
v= 90 km/hr
converting velocity in m/s we get
v= 25 m/s
As train start from rest it's initial velocity u=0
using formula for acceleration
a=( v-u)/t
5= (25-0)/t
t= 25/5
t= sec
Using second kinematical equation
S= ut + 1/2 at square
S= 0×5 + 1/2 × 5 × (5)^2
S= 1/2 × 125
S= 125/2
S= 62.5 m
a= 5m/s^2
v= 90 km/hr
converting velocity in m/s we get
v= 25 m/s
As train start from rest it's initial velocity u=0
using formula for acceleration
a=( v-u)/t
5= (25-0)/t
t= 25/5
t= sec
Using second kinematical equation
S= ut + 1/2 at square
S= 0×5 + 1/2 × 5 × (5)^2
S= 1/2 × 125
S= 125/2
S= 62.5 m
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