Question

the diagonal AC & BD of rhombus ABCD are 24 and 10 cm respectively .find the area of the rhombus and also it's side

Answer 1

area =120 sq. cm
side =13 cm

Answer 2

Hi ,

Let d1, d2 are the diagonals of the

given Rhombus ,

d1 = 24cm ,

d2 = 10 cm

Area ( A ) = ( d1d2 ) /2

A = ( 24 × 10 ) /2

A = 120 cm²

Now ,

In ABCD Rhombus AC , BD diagonals

perpendicularly bisect each other at

' O ' .

Therefore ,

In ∆ AOB ,

< AOB = 90°

AB² = OA² + OB²

= ( d1/2 )² + ( d2/2 )²

= ( 24/2 )² + ( 10/2 )²

= 12² + 5²

= 144 + 25

= 169

AB = √169

= √13²

AB = 13 cm

Therefore ,

Side of the Rhombus = 13 cm

I hope this helps you.

:)